4CuFeS_{2} + 9O_{2} → 2Cu_{2}S + 6SO_{2} + 2Fe_{2}O_{3}

Bạn đang xem: cufes2 + o2 = cu2s + so2 + fe2o3

⬇ Scroll down to tát see reaction info and a step-by-step answer, or balance another equation.

### Word Equation

Chalcopyrite + Dioxygen = Chalcocite + Sulfur Dioxide + Hematite

Four moles of

and nine moles of

react to tát form two moles of

, six moles of

and two moles of

### Products

### Chalcocite - Cu

_{2}S### Sulfur Dioxide - SO

_{2}Sulphur Dioxide R-764 Sulfurous Anhydride So2 Sulphur Dioxide , Sulfur Dioxide Sulfur Oxide Sulfurous Oxide Sulfurous Acid Anhydride SO2 Molar Mass SO2 Oxidation Number

### Hematite - Fe

_{2}O_{3}

### Reaction Expressions

K_{c} or Q = ( [Cu_{2}S]^{2} [SO_{2}]^{6} [Fe_{2}O_{3}]^{2} ) / ( [CuFeS_{2}]^{4} [O_{2}]^{9} )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -1/4 * (Δ[CuFeS_{2}] / Δt) = -1/9 * (Δ[O_{2}] / Δt) = 50% * (Δ[Cu_{2}S] / Δt) = 1/6 * (Δ[SO_{2}] / Δt) = 50% * (Δ[Fe_{2}O_{3}] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)

## Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- Ionic charges are not yet supported and will be ignored.
- Replace immutable groups in compounds to tát avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
- Compound states [like (s) (aq) or (g)] are not required.
- You can use parenthesis () or brackets [].

## How To Balance Equations

Read our article on how to tát balance chemical equations or ask for help in our chat.

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## Balance CuFeS2 + O2 = Cu2S + SO2 + Fe2O3 Using the Algebraic Method

To balance the equation CuFeS2 + O2 = Cu2S + SO2 + Fe2O3 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

### Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to tát represent the unknown coefficients.

a CuFeS

_{2}+ b O_{2}= c Cu_{2}S + d SO_{2}+ f Fe_{2}O_{3}### Create a System of Equations

Create an equation for each element (Cu, Fe, S, O) where each term represents the number of atoms of the element in each reactant or product.

Xem thêm: lẩu lươn lá giang

**Cu**: 1a + 0b = 2c + 0d + 0f**Fe**: 1a + 0b = 0c + 0d + 2f**S**: 2a + 0b = 1c + 1d + 0f**O**: 0a + 2b = 0c + 2d + 3f### Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to tát solve for each variable.

- 1a - 2c = 0
- 1a - 2f = 0
- 2a - 1c - 1d = 0
- 2b - 2d - 3f = 0

Use your graphing calculator's rref() function (or an online rref calculator) to tát convert the following matrix into reduced row-echelon-form:

[ 1 0 -2 0 0 0] [ 1 0 0 0 -2 0] [ 2 0 -1 -1 0 0] [ 0 2 0 -2 -3 0]

The resulting matrix can be used to tát determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result to tát get the lowest, whole integer values.

- a = 4 (CuFeS2)
- b = 9 (O2)
- c = 2 (Cu2S)
- d = 6 (SO2)
- f = 2 (Fe2O3)

### Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

4 CuFeS

_{2}+ 9 O_{2}= 2 Cu_{2}S + 6 SO_{2}+ 2 Fe_{2}O_{3}Reactants Products Cu 4 4 ✔️ Fe 4 4 ✔️ S 8 8 ✔️ O 18 18 ✔️ Since there is an equal number of each element in the reactants and products of 4CuFeS2 + 9O2 = 2Cu2S + 6SO2 + 2Fe2O3, the equation is balanced.

## Balance CuFeS2 + O2 = Cu2S + SO2 + Fe2O3 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the over of a chemical reaction as at the beginning. To be balanced, every element in CuFeS2 + O2 = Cu2S + SO2 + Fe2O3 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to tát balance one element at a time until both sides are equal and the chemical equation is balanced.

### 1. Count the number of each element on the left and right hand sides

Reactants (Left Hand Side) | Products (Right Hand Side) | |||||||
---|---|---|---|---|---|---|---|---|

Reactants | Products | |||||||

CuFeS_{2} | O_{2} | Total | Cu_{2}S | SO_{2} | Fe_{2}O_{3} | Total | ||

Cu | 1 | 1 | 2 | 2 | ❌ | |||

Fe | 1 | 1 | 2 | 2 | ❌ | |||

S | 2 | 2 | 1 | 1 | 2 | ✔️ | ||

O | 2 | 2 | 2 | 3 | 5 | ❌ |

### 2. Multiply coefficients for compounds to tát balance out each element

For each element that is not equal, try to tát balance it by adding more of it to tát the side with less. Sometimes there may be multiple compounds with that element on one side, sánh you'll need to tát use your best judgement and be prepared to tát go back and try the other options.

**Cu**is not balanced. Add**1**molecule of**CuFeS**to tát the reactant (left-hand) side to tát balance Copper:_{2}

2CuFeS_{2}+ O_{2}= Cu_{2}S + SO_{2}+ Fe_{2}O_{3}Reactants Products Cu 2 2 ✔️ Fe 2 2 ✔️ S 4 2 ❌ O 2 5 ❌ **S**is not balanced. Add**1**molecule of**Cu**to tát the product (right-hand) side to tát balance Sulfur:_{2}S

2CuFeS_{2}+ O_{2}= 2Cu_{2}S + SO_{2}+ Fe_{2}O_{3}Reactants Products Cu 2 4 ❌ Fe 2 2 ✔️ S 4 3 ❌ O 2 5 ❌ **Cu**is not balanced. Add**2**molecules of**CuFeS**to tát the reactant (left-hand) side to tát balance Copper:_{2}

4CuFeS_{2}+ O_{2}= 2Cu_{2}S + SO_{2}+ Fe_{2}O_{3}Reactants Products Cu 4 4 ✔️ Fe 4 2 ❌ S 8 3 ❌ O 2 5 ❌ **Fe**is not balanced. Add**1**molecule of**Fe**to tát the product (right-hand) side to tát balance Iron:_{2}O_{3}

4CuFeS_{2}+ O_{2}= 2Cu_{2}S + SO_{2}+ 2Fe_{2}O_{3}Reactants Products Cu 4 4 ✔️ Fe 4 4 ✔️ S 8 3 ❌ O 2 8 ❌ **S**is not balanced. Add**5**molecules of**SO**to tát the product (right-hand) side to tát balance Sulfur:_{2}

4CuFeS_{2}+ O_{2}= 2Cu_{2}S + 6SO_{2}+ 2Fe_{2}O_{3}Reactants Products Cu 4 4 ✔️ Fe 4 4 ✔️ S 8 8 ✔️ O 2 18 ❌ **O**is not balanced. Add**8**molecules of**O**to tát the reactant (left-hand) side to tát balance Oxygen:_{2}

4CuFeS_{2}+ 9O_{2}= 2Cu_{2}S + 6SO_{2}+ 2Fe_{2}O_{3}Reactants Products Cu 4 4 ✔️ Fe 4 4 ✔️ S 8 8 ✔️ O 18 18 ✔️

### 3. Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

4CuFeS_{2} + 9O_{2} = 2Cu_{2}S + 6SO_{2} + 2Fe_{2}O_{3}

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